The correct order of ionisation energy of C, N, O and F is
C < N < O < F
C < O < N < F
F < O < N < C
F < N < C < O
B.
C < O < N < F
On moving from left to right in a period, ionisation energy increases. Thus, correct order of ionisation energy of C, N, O, F should be
C < N < O < F
But the ionisation energy of N is found to be greater than that of O. This is due to the presence of half-filled p-orbitals in N which provide it extra stability. Thus, the correct order is C < O < N < F.
A metallic oxide reacts with water to from its hydroxide, hydrogen peroxide and also liberates oxygen. The metallic oxide could be
CaO
KO2
Li2O
Na2O2
Pauling's electronegativity values for elements are useful in predicting :
polarity of bonds in molecules
position of elements in electromotive series
co-ordination number
dipole moment of various molecules
Which of the following pairs involves isoelectronic ions ?
Mn3+ and Fe2+
Mn2+ and Fe3+
Cr3+ and Mn2+
Fe2+ and Co2+
Which is the correct order of electronegativity?
F > N < O < C
F > N > O > C
F > N > O < C
F < N < O = C