Alkanes and alkynes do not exhibit geometrical isomerism. Explain.
Alkanes contain carbon-carbon single bond and there is free rotation around single bond or sigma bond. Alkynes contain triple bond around which the rotation is hindered but the molecule is linear. Therefore, the question of fixed arrangement does not arise. Hence alkanes and alkynes do not show geometrical isomerism.
What happens when butan-2-ol is heated with concentrated H2SO4. Account for the product formed.
How will you explain that there exists two varieties of 1, 2,-dichloroethene while there is only one type of 1, 2-dichloroethane?
What happens when 2-Bromobutane is heated with alcoholic KOH. Account for the product formed.
Draw the cis and trans structures of hex-2-ene. Which isomer will have higher b.p. and why?
Which of the following compounds will show cis-trans isomerism?
(i)(CH3)2C = CH-C2H5
(ii) CH2 = CBr2
(iii) C2H5CH = CH-CH2
(iv) CH3CH = CClCH3
Draw cis and trans isomers of the following compounds. Also, write their IUPAC names:
(i) CHCl = CHCl
(ii) C2H5CCH3 = CCH3C2H5
