Long Answer Type

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How will you explain that there exists two varieties of 1, 2,-dichloroethene while there is only one type of 1, 2-dichloroethane?


The structure of 1, 2-dichloroethene is



Since in the above structure there is C = C bond and two chlorine atoms are present at two different carbon atoms, therefore, it is capable of exhibiting geometrical isomerism. The two geometrical isomers (i.e. two varieties) of the above compound can be represented as:



The structure of 1, 2-dichloroethane is



The molecule has C-C bond. As the rotation of the atoms or groups about single bond is quite free, the compound fails to show geometrical isomerism. 




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Short Answer Type

What is Saytzeff’s rule? Explain it with an example. 

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Which of the following compounds will show cis-trans isomerism?

(i)(CH3)2C = CH-C2H5
(ii) CH2 = CBr2
(iii) C2H5CH = CH-CH2
(iv) CH3CH = CClCH3 

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Which of the following compounds would show geometrical isomerism? Draw the isomeric structures to support your answer:
(i) But-2-ene
(ii) Pent-1-ene
(iii) 2-Methyl-But -2-ene
(iv) 3, 4-Dimethyl-hex-3-ene

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Draw cis and trans isomers of the following compounds. Also, write their IUPAC names:

(i) CHCl = CHCl

(ii) C2H5CCH3 = CCH3C2H5 

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What happens when butan-2-ol is heated with concentrated H2SO4. Account for the product formed.

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Alkanes and alkynes do not exhibit geometrical isomerism. Explain. 

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Out of the two - trans-but-2-ene and cis-but-1-ene, which is more stable and why

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What happens when 2-Bromobutane is heated with alcoholic KOH. Account for the product formed.

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Draw the cis and trans structures of hex-2-ene. Which isomer will have higher b.p. and why?

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