Short Answer TypeWrite the structures of main products when aniline reacts with the following reagents:
(i) Br2 water
(ii) HCl
(iii) (CH3CO)2O/pyridine
Arrange the following in the increasing order of their boiling point: C2H5NH2, C2H5OH, (CH3)3N
Give a simple chemical test to distinguish between the following pair of compounds:
(CH3)2NH and (CH3)3N.
Arrange the following compounds in increasing order of solubility in water:
C6H5NH2, (C2H5)2NH, C2H5NH2
Arrange the following compounds in an increasing order of their solubility in water:
C6H5NH2, (C2H5)2NH, C2H5NH2The solubility order of the given amines is as follows:
C6H5NH2 < (C2H5)2NH < C2H5NH2
The more extensive the Hydrogen bonding, the higher is the solubility. C2H5NH2 contains two H-atoms whereas (C2H5)2NH contains only one H-atom. Thus, C2H5NH2undergoes more extensive. Hydrogen bonding than (C2H5)2NH. Hence, the solubility in water of C2H5NH2 is more than that of (C2H5)2NH.
Further, the solubility of amines decreases with increase in the molecular mass. This is because the molecular mass of amines increases with an increase in the size of the hydrophobic part.
The molecular mass of C6H5NH2 is greater than that of C2H5NH2 and (C2H5)2NH.
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