How many tripeptides can be prepared by linking the amino acids g

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 Multiple Choice QuestionsMultiple Choice Questions

461.

Which of the following compound is the most basic?


462.

The product formed when phthalimide is treated with a mixture of Br2 and strong NaOH solution is

  • aniline

  • phthalamide

  • phthalic acid

  • anthranilic acid


463.

p-toluidine and benzyl amine can be distinguished by

  • Sandmeyer's reaction

  • Dye test

  • Molisch test

  • Gattermann reaction


464.

Which one of the following will be most basic?

  • Aniline

  • p-methoxyaniline

  • p-methyl aniline

  • Benzylamine


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465.

Nitrobenzene can be converted into azobenzene by reduction with

  • Zn, NH4Cl, 

  • Zn/NaOH, CH3OH

  • Zn/NaOH

  • LiAlH4, ether


466.

The one which is least basic is

  • NH3

  • C6H5NH2

  • (C6H5)3N

  • (C6H5)2NH


467.

Which of the following converts CH3CONH2 to CH3NH2?

  • NaBr

  • NaOBr

  • Br2

  • None of the above


468.

The reaction, ROH + H2CN2 in the presence of HBF4, gives the following product

  • ROCH3

  • RCH2OH

  • ROHCN2N2

  • RCH2CH3


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469.

In Gattermann reaction, a diazonium group is replaced by X using Y.X and Y are

  • X Y
    Cl Cu/HCl
  • X Y
    Cl CuCl2/HCl
  • X Y
    Cl CuCl2/HCl
  • X Y
    Cl2 Cu2O/HCl

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470.

How many tripeptides can be prepared by linking the amino acids glycine, alanine and phenyl alanine?

  • One

  • Three

  • Six

  • Twelve


C.

Six

Tripeptides are amino acids polymers in which three individual amino acid units, called residues, are linked together by amide bonds. In these, an amine group from one residue forms an amide bond with the carboxyl group of a second residue, the amino group of the second forms an amide bond with the carboxyl group of the third.

Therefore, glycine (NH2-CH2-COOH), alanine (CH3CH(NH2)-COOH) and phenyl alanine C6H5-CH2-NH2CHCOOH can be linked in six different way.


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