Carbylamine reaction is given by aliphatic : from Chemistry Amin

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 Multiple Choice QuestionsMultiple Choice Questions

471.

Consider the following reaction,

C2H5HCl + AgCN EtOH/H2O X (major)

Which one of the following statements is true for X ?

(I) It gives propionic acid on hydrolysis
(II) It has an ester functional group
(III) It has a nitrogen linked to ethyl carbon
(IV) It has a cyanide group

  • IV

  • III

  • II

  • I


472.

When acetamide is hydrolysed by boiling with acid, the product obtained is

  • acetic acid

  • ethyl amine

  • ethanol

  • acetamide


473.

Which will not go for diazotisation?

  • C6H5NH2

  • C6H5CH2NH2


474.

Urea on slow heating gives :

  • NH2CONHNO2

  • NH2CONHCONH2

  • HCNO

  • NH2CONH2.HNO3


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475.

The correct sequence of base strengths in aqueous solution is :

  • (CH3)2NH > CH3NH2 > (CH3)3N

  • (CH3)3N > CH3NH>(CH3)2NH

  • (CH3)3N > CH3NH2 = (CH3)2NH

  • (CH3)2NH > (CH3)3N > CH3NH2 


476.

When aqueous solution of benzene diazoniumchloride is boiled, the product formed is:

  • C6H5CH2OH

  • C6H+ N2

  • C6H5COOH

  • C6H5OH


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477.

Carbylamine reaction is given by aliphatic :

  • primary amine

  • secondary amine

  • tertiary amine

  • quaternary ammonium salt


A.

primary amine

Carbylamine reaction is given by aliphatic and aromatic primary amine hence, it can be used for the distinguish of primary amine with secondary and tertiary amine. In this reaction a primary amine reacts with chloroform and alcoholic KOH  to give poisonous substance isocyanide.

RNH2primary amine + CHCl3 + 3KOH(alc)  RNCalkyl isocyanide    +  3KCl + 3H2O


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478.

C6H5CHO  NH3 ?

  • (C6H5CHN)2CH·C6H5

  • C6H5NHCH3

  • C6H5NHCH2

  • C6H5NHC6H5


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479.

An organic compound 'A' having molecular formula C2H3N on reduction gave another compound B, upon treatment with nitrous acid 'B' gave ethyl alcohol. On warming with chloroform and alcoholic KOH, it formed an offensive smelling compound 'C'. The compound 'C' is

  • CH3CH2NH2

  • CH3CH2N= C

  • CH3CN

  • CH3CH2.OH


480.

Compound (A) (molecular formula C3H8O) is treated with acidified potassium dichromate to form a product B (molecular formula C3H6O). 'B' forms a shining silver mirror on warming with ammoniacal silver nitrate. 'B' when treated with an aqueous solution of H2NCONHNH2 · HCl and sodium acetate gives a product C'. Identify the structure of 'C

  • CH3CH2CH =NNHCONH2

  • (CH3)2C = NNHCONH2

  • (CH3)2C =NCONHNH2

  • CH3CH2CH= NCONHNH2


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