Gabriel's phthalimide synthesis can be used to prepare from Chem

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

511.

0ne mole of hydrazine (N2H4) loses 10 moles of electrons in a reaction to form a new compound X. Assuming that all the nitrogen atoms in hydrazine appear in the new compound, what is the oxidation state of nitrogen in X? (Note - There is no change in the oxidation state of hydrogen in the reaction).

  • -1

  • -3

  • +3

  • +5


512.

Which one of the following is used as a test for aliphatic primary amines?

  • Tollen's test

  • Fehling's test

  • lsocyanide test

  • Azo dye test


513.

When methanamine is treated with benzoyl chloride, the major product is

  • N-phenylethanamide

  • N-methylbenzamide

  • benzanilide

  • acetophenone


514.

Phenyl isocyanide is prepared from aniline by

  • Carbylamine reaction

  • Rosenmund's reaction

  • Koble's reaction

  • Reimer-Tiemann reaction


Advertisement
Advertisement

515.

Gabriel's phthalimide synthesis can be used to prepare

  • ethanamine

  • N-methylmethanamine

  • benzene amine

  • N, N-dimethylmethanamine


A.

ethanamine

Only aliphatic primary amines are synthesised by Gabriel's phthalimide synthesis. The structures of the given compounds are as follows-

(i) C2H5NH2 or ethanamine

(ii) CH3NHCH3 or N-methylmethanamine

(iii)  or benzeneamine

(iv)  or p-toulidine

Thus, among all the given options, only ethanamine can be obtained from Gabriel's phthalimide synthesis.


Advertisement
516.

Select the compound which on treatment with nitrous acid liberates nitrogen.

  • Nitroethane

  • Triethylamine

  • Diethylamine

  • Ethylamine


517.

The compound that neither forms semicarbazone nor oxime is

  • HCHO

  • CH3COCH3

  • CH3CHO

  • CH3CH2CH2NH2


518.

Positive carbylamine test is shown by

  • N, N-dimethylaniline

  • triethylamine

  • N-methylaniline

  • p-methylbenzylamine


Advertisement
519.

Ethanoic acid on heating with ammonia forms compound A which on treatment with bromine and sodium hydroxide gives compound B. Compound B on treatment with NaNO3/dil.HCl gives compound C. The compounds A, B and C respectively are

  • ethanamide, methanamine, methanol

  • propanamide, ethanamine, ethanol

  • N-ethylpropanamide, methaneisonitrile, methanamine

  • ethanamine, bromoethane, ethanediazoniumchloride


520.

n-butylamine (l),  diethylamine (II) and N,  N-dimethylethylamine (III)  have the same molar mass.  The increasing order of their boiling point is

  • III < II < I

  • I < II < III

  • II < III < I

  • II < I < III


Advertisement