In the following reaction, X and Y are respectively

CH₃COOH + NH₃ → X $\stackrel{∆}{\to }$ Y + H₂O

• CH₃CONH₂, CH₄

• CH₃COONH₄, CH₃CONH₂

• CH₃CONH₂, CH₃COOH

• CH₃NH₂, CH₃CONH₂

542.

Which one of the following is the molecular formula of a tertiary amine ?

• C₂H₇N

• C₃H₉N

• CH₅N

• CH₃N

Aniline is not the major product in one of the following reactions. Identify that reaction

• ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{OH} + {\mathrm{NH}}_3 \underset{300°\mathrm{C}}{\overset{ {\mathrm{ZnCl}}_2}{\to }}$

• ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NO}}_2 + \mathrm{Zn} \mathrm{powder}\hspace{0.17em}\stackrel{\mathrm{alcoholic} \mathrm{KOH}}{\to }$

• ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{Cl} +{\mathrm{NH}}_3 \underset{{\mathrm{Cu}}_2\mathrm{O}}{\overset{ 200°\mathrm{C}}{\to }} \mathrm{high} \mathrm{pressure}$

• ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NO}}_2 + 6\left(\mathrm{H}\right) \underset{\mathrm{HCl}}{\overset{\mathrm{Fe} +{\mathrm{H}}_2\mathrm{O}}{\to }}$

Which one of the following compounds forms a quaternary salt on reacting with excess methyl iodide?

• C₂H₅OCH₃

• (CH₃)₂CHOC₂H₅

• C₆H₅NH₂

• C₆H₅NO₂

Nitrobenzene on reduction with zinc and NH₄Cl gives

• azobenzene

• aniline

• hydrazobenzene

• N-phenyl hydroxylamine

In Gattermann reaction, a diazonium group is replaced by $\underline{\mathrm{X}}$ using $\underline{\mathrm{Y}}$. $\underline{\mathrm{X}}$ and $\underline{\mathrm{Y}}$ are-

• $\underline{\mathrm{X}}$ - ${\mathrm{Cl}}^{⊝}$; $\underline{\mathrm{Y}}$ - Cu/ HCl 

• $\underline{\mathrm{X}}$ - ${\mathrm{Cl}}^{\oplus }$ ; $\underline{\mathrm{Y}}$ - CuCl₂/ HCl

• $\underline{\mathrm{X}}$ - ${\mathrm{Cl}}^{⊝}$; $\underline{\mathrm{Y}}$ - CuCl₂/ HCl

• $\underline{\mathrm{X}}$ - Cl₂ ; $\underline{\mathrm{Y}}$ - Cu₂O/ HCl

What is the product obtained in the reaction of acetaldehyde with semicarbazide ?

• ${\mathrm{H}}_3\mathrm{C}-\mathrm{CH}=\mathrm{N}-{\mathrm{NHCONH}}_2$

• ${\mathrm{H}}_3\mathrm{C}-\mathrm{CH}=\mathrm{N}-{\mathrm{NH}}_2$

• ${\mathrm{H}}_3\mathrm{C}-\mathrm{CH}=\mathrm{N}-\mathrm{OH}$

• ${\mathrm{H}}_3\mathrm{C}-{\mathrm{CCH}}_3=\mathrm{N}-\mathrm{NH}-\mathrm{CO}-{\mathrm{NH}}_2$

Yellow dye can be prepared by a coupling reaction of benzene diazonium chloride in acidic medium with X. Identify X from the following.

• Aniline

• Phenol

• Cumene

• Benzene

Acid hydrolysis of methyl isocyanide gives

• CH₃NH₂ + HCOOH

• CH₃NH₂ + CH₃COOH

• CH₃NH₂ + CH₃CH₂COOH

• CH₃NH₂ + (CH₃)₂CHCOOH

Mark the correct statement.

• Methyl amine is acidic.

• Methyl amine is less basic than NH₃.

• Methyl amine is a stronger base than NH₃.

• Methyl amine forms salts with bases.