Consider the following compounds:Correct order of the basic natur

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671.

Consider the following compounds:

Correct order of the basic nature of the above compounds:

 

  • I<II<III<IV

  • IV<II<III<I

  • I<III<IV<II

  • II<IV<III<I


A.

I<II<III<IV

I 10 alkyl< II (iso alkyl) <III (20 alkyl) < IV ( 30 alkyl)


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672.

The correct order of basicity of:

  • A> B > C > D

  • D > C>A> B

  • B > D > C > A

  • D>A> B > C


673.

Consider the following consersion,

The reagent 'X' will be:

  • H3PO2

  • Cu2Cl2

  • HgSO4/H2SO4

  • H+/H2O


674.

Aniline when diazotised in cold and then treated with dimethyl aniline gives a coloured product. The structure of coloured product would be:


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675.

Which ofthe following reactions will not give a primary amine?

  • CH3NC LiAlH4

  • CH3CN LiAlH4

  • CH3CONH2 LiAlH4

  • CH3CONH2Br2/KOH


676.

In the given reaction,

Br2/Fe X Sn/HCl Y

The products X and Y respectively are:

  • o-bromo nitrobenzene and o-bromoaniline

  • p-bromo nitrobenzene and p-bromoaniline

  • m-bromo nitrobenzene and m-bromoaniline

  • m-bromo nitrobenzene and m-bromoaniline


677.

Hexamethylenetetramine is used as

  • urinary antiseptic

  • antipyretic

  • analgesic

  • all of these


678.

Arrange the following in the increasing order of their basic strengths :

CH3NH2 , (CH3)2NH , (CH3)3N , NH3

  • NH3 < (CH3)3N < (CH3)2NH < CH3NH2

  • NH< (CH3)3N < CH3NH< (CH3)2NH

  • (CH3)3N < NH< CH3NH2 < (CH3)2NH

  • CH3NH< (CH3)2NH < (CH3)3N < NH


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679.

Assertion : Benzene reacts with iodine monochloride in presence of anhyd. AlCl3 to form iodobenzene.

Reason : Iodine monochloride reacts with anhyd. AlCl3 to produce I+ which attacks the benzene ring.

  • If both assertion and reason are true and reason is the correct explanation of assertion

  • If both assertion and reason are true but reason is not the correct explanation of assertion.

  • If assertion is true but reason is false.

  • If both assertion and reason are false.


680.

Which amine amongst the following will answer positively the carbylamine test?

  • C6H5 - NH - CH3

  • C6H5 - NH - C4H9

  • C6H5 - N(C2H5)2


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