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 Multiple Choice QuestionsMultiple Choice Questions

691.

Nitrobenzene (PhNO2Zn + NH4ClP ?

  • C6H5NH2

  • C6H5NHOH

  • C6H5-N=O

  • C6H6


692.

PhCH2Cla.q. NaCl? Catalytic hydrogenation(U)

The final product (U) is:

  • C6H5CH2CH2NH2

  • C6H5CH2CONH2

  • C6H5CH2NH2

  • C6H5CH2NHCH3


693.

Among the following, the correct order of basicity is :

  • NH2- > OH- > RO- > RCOO-

  • NH2- > RO- > OH- > RCOO-

  • RCOO- > NH2- > RO- > OH-

  • RCOO- > RO- > NH2- > OH-


694.

Amides are converted to amines by the following reaction :

  • Perkin

  • Claisen

  • Hofmann

  • Clemmensen


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695.

N2 gas is liberated when [HCl + NaNO2] reacts with the following compound :

(A) CH3CH2NH2   (B) Urea

(C) CH3CONH2    (D) C6H5NH2

The answer is :

  • A , B , C

  • A , B , D

  • A, C , D

  • B , C , D


696.

Acetamide when heated with PCl5 gives :

  • CH3Cl

  • CH3CN

  • CH3CCl2NH2

  • CHCl2CONH2


697.

Which of the following reactions does not yield an amine?

  • R-X + NH3 

  • R-CH=NOH + [H] NaC2H5OH

  • R-CN +H2H+

  • R-CONH2 LiAlH4


698.

The chemical name for melamine is

  • 1,3,5-Triamino-2,4,6-triazine

  • 2,4,6-Triamino-1,3,5-triazine

  • 2-Amino-1,3,5-triazine

  • 2,4-Diamino-1,3,5-triazine


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699.

Bromine is added to cold dilute aqueous solution ofNaOH. The mixture is boiled. Which of the following statements is not true?

  • During the reaction bromine is present in four different oxidation states.

  • The greatest difference between the various oxidation states of bromine is 5.

  • On acidification ofthe final mixture bromine is formed.

  • Disproportionation of bromine occurs during the reaction.


B.

The greatest difference between the various oxidation states of bromine is 5.

2NaOH(dilute)+Br  coldNaBrO + NaBr + H2O

3NaBrNoSodiumhypobromide  300k3NaBrO

On acidification, the final mixture give bromin.

5NaBrO3 + NaBrO3 + 6HCl 6NaCl +3Br2 + 3H2O

Thus, during the reaction, bromine is present in four different oxidation states i.e., zero in Br2, +1 in NaBrO, -1 in NaBr and +5 in NaBrO3. The greatest difference between various oxidation states of bromine is 6 and not 5. On acidification of the final mixture, Bris formed and disproportionation of Broccurs during the reaction giving BrO-, Br- and BrO3-  ions.


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700.

RNO2 is reduced with Sn/HCl .Product formed is :

  • RNHOH

  • RNH2

  • RNH3+

  • R2NH


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