Long Answer TypeDiscuss the shape of the following molecules using VSEPR model:
BeCl2, BCl3, SiCl4, AsF5, H2S, PH3
BeCl2:
Lewis dot structure Cl: Be : Cl. The central atom (Be) has only two bond pairs and no lone pair. Hence shape is linear.
BCl3:
The central atom (B) has only three bond pairs and no lone pair. Hence shape is triangular planar.
SiCl4:
The central atom (Si) has four bond pairs and no lone pair. Hence the shape is tetrahedral.
AsF5:
The central atoms (As) has five bond pairs and no lon∈ pair. Hence, the shape is trigonal bipyramidal.
H2S:
The central atom (S) has two bond pairs and two lone pairs. Hence, the shape is Bent or V-shaped.
PH3:
The central atom (P) has three bond pairs and two lone pairs. Hence, the shape is. Bent or V-shaped.
Short Answer TypeLong Answer TypeDiscuss in brief sp2 hybridization (hybridization in C = C bond). Discuss the molecular orbital structure of ethylene (first member of alkene).
Or
Draw diagrams showing the formation of a double bond between carbon atoms in C2H4.
Short Answer TypeApart from tetrahedral geometry, another possible geometry for CH4 is square planar with four H atoms at the corners of the square and the C atom at its centre. Explain why CH4 is not square planar?
Long Answer TypeShort Answer TypeThe central atoms in CH4, NH3 and H2O are all said to have similar hybridisation but the bond angle H – A – H (where A is C, N or O) is different in each case. Explain stating in which case it is maximum and in which case it is minimum.
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