State and explain hybridisation. from Chemistry Chemical Bondi

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 Multiple Choice QuestionsLong Answer Type

171.

On the basis of VSEPR theory, predict the shapes of given molecules: PCl5 and SF6.

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172.

Discuss the shape of the following molecules using VSEPR model:
BeCl2, BCl3, SiCl4, AsF5, H2S, PH3

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173.

State and explain hybridisation.


The phenomenon of intermixing of atomic orbitals of slightly different enthalpies of an atom so as to redistribute their enthalpies to form the same number of new orbitals of equivalent enthalpies and identical shapes is called hybridization. The new orbitals, thus formed are called hybrid orbitals or hybridised orbitals.

Explanation : In order to understand hybridisation, let us take an example of carbon (Z= 6). Its ground state electronic configuration is,




Since it has two half filled orbitals, therefore, the valency of the carbon atom should be 2. But actually, carbon atom always exhibits a valency of four (tetravalent). To achieve this, an electron is promoted from 2s filled orbital to the vacant higher enthalpy 2p orbital. This is called excited state of a carbon atom.




In the excited state of carbon s and p, orbitals have different enthalpies. Consequently, four bonds of carbon must be of two types. Three of the bonds should be of one type (s - p bonds) while fourth bond should be a different type (s - s bond). However, experimental evidence indicates that all the four bonds in case of CH4 (methane) are equivalent. To explain the equivalence of all the four bonds in case of methane, the concept of hybridisation is used i.e. all the four orbitals in the valence shell of carbon may get mixed, redistribute enthalpies and give orbitals of new enthalpy and shape. These equivalent orbitals are called hybrid orbitals.

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 Multiple Choice QuestionsShort Answer Type

174.

What are the necessary conditions for hybridisation?

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175.

What are the different types of hybridisation in s and p atomic orbitals?

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 Multiple Choice QuestionsLong Answer Type

176.

Discuss in brief sp3 hybridisation. Explain the formation of methane and ethane.

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177.

Discuss in brief sp2 hybridization (hybridization in C = C bond). Discuss the molecular orbital structure of ethylene (first member of alkene).

Or

Draw diagrams showing the formation of a double bond between carbon atoms in C2H4.

 

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 Multiple Choice QuestionsShort Answer Type

178.

Apart from tetrahedral geometry, another possible geometry for CH4 is square planar with four H atoms at the corners of the square and the C atom at its centre. Explain why CH4 is not square planar?

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 Multiple Choice QuestionsLong Answer Type

179.

On the basis of hybridisation, discuss the orbital structure of: (i) BeF2 (ii) BH3.

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 Multiple Choice QuestionsShort Answer Type

180.

The central atoms in CH4, NH3 and H2O are all said to have similar hybridisation but the bond angle H – A – H (where A is C, N or O) is different in each case. Explain stating in which case it is maximum and in which case it is minimum.

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