On the basis of hybridisation, discuss the orbital structure of

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 Multiple Choice QuestionsLong Answer Type

171.

On the basis of VSEPR theory, predict the shapes of given molecules: PCl5 and SF6.

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172.

Discuss the shape of the following molecules using VSEPR model:
BeCl2, BCl3, SiCl4, AsF5, H2S, PH3

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173.

State and explain hybridisation.

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 Multiple Choice QuestionsShort Answer Type

174.

What are the necessary conditions for hybridisation?

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175.

What are the different types of hybridisation in s and p atomic orbitals?

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 Multiple Choice QuestionsLong Answer Type

176.

Discuss in brief sp3 hybridisation. Explain the formation of methane and ethane.

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177.

Discuss in brief sp2 hybridization (hybridization in C = C bond). Discuss the molecular orbital structure of ethylene (first member of alkene).

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Draw diagrams showing the formation of a double bond between carbon atoms in C2H4.

 

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 Multiple Choice QuestionsShort Answer Type

178.

Apart from tetrahedral geometry, another possible geometry for CH4 is square planar with four H atoms at the corners of the square and the C atom at its centre. Explain why CH4 is not square planar?

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 Multiple Choice QuestionsLong Answer Type

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179.

On the basis of hybridisation, discuss the orbital structure of: (i) BeF2 (ii) BH3.


(i) Orbital structure of BeF2 :



To form BeF2 molecule, an electron gets promoted from filled 2s orbital to vacant 2p orbital. Therefore, the excited configuration of Be atom is



In BeF2, Be atom is sp hybridised i.e. two hybrid orbitals are directed along a straight line with a bond angle equal to 180°. Each sp hybrid orbital overlaps axially with 2p half-filled orbital of F atom to form sigma Be – F bonds.



(ii) Orbital structure of BH3:
The electronic configuration of B (Z = 5) is 1s2 2s22P1.





In BH3, B atom is sp2 hybridised and the three hybrid orbitals overlap axially with the orbital of the hydrogen atom to from three sigma B–H bonds.



The shape is trigonal planar.

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 Multiple Choice QuestionsShort Answer Type

180.

The central atoms in CH4, NH3 and H2O are all said to have similar hybridisation but the bond angle H – A – H (where A is C, N or O) is different in each case. Explain stating in which case it is maximum and in which case it is minimum.

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