What is meant by hybridization of atomic orbitals? Describe the shapes of sp, sp2, sp3 hybrid orbitals.
Descibe the hybridisation in case of PCl5. Why are the axial bonds longer as compared to equatorial bonds?
Hybridization is the phenomenon of intermixing of atomic orbitals of slightly different energies of the atoms by redistributing their energies to form a new set of orbitals of equivalent energies and identical shape.
Atomic number of phosphorus P=15.
Electronic configuration of P
Ground state 1s2 2s2 3s2 3p3 3d0
Electronic configuration of P
excited state 1s2 2s2 3s1 3p3 3d1
Now phosphorus has five empty shells, five Cl hybridised to form an equal set of equivalent five sp3d hybrid orbitals. These 5 sp3d orbitals are directed towards the five corners of a trigonal bipyramidal geometry.
In PCl5, out of the five hybrid orbitals, three orbitals form a P-Cl bond in one plane making and angle (P-Cl-P) 120 with each other. This plane is represented as equatorial plane and the bonds formed are equatorial bonds. Out of the remaining two hybrid orbitals, one lie perpendicularly above and the other lie perpendicularly above and the other lie perpendicularly below the equatorial plane, making an angle 90 with the plane and forms P-Cl bonds. These two bonds are called axial bonds. Since the axial bonds suffer more repulsive interaction from the equatorial bond pairs, they are found to be slightly longer and hence, slightly weaker than the equatorial bonds.
The species in which the N atom is in a state of sp hybridization is:
NO2-
NO3-
NO2
NO2
The ionic radii (in Å) of N3–, O2– and F– are respectively:
1.36, 1.40 and 1.71
1.36, 1.71 and 1.40
1.71, 1.40 and 1.36
1.71, 1.40 and 1.36
In which of the following pairs of molecules/ions, both the species are not likely exist?
Which of the following exists as covalent crystals in the solid state?
Iodine
Silicon
Sulphur
Sulphur