If the value of bond order is zero, then
molecule will be stable
molecule will be unstable
molecule will be in ionic state
None of the above
Which of the following is a proper match?
Shape | |
A. 0.115 - 0.225 | i. Triangular |
B. 0.225 - 0.414 | ii. Tetrahedral |
C. 0.414 - 0.732 | iii. Cubic |
D. 0.732 - 1 | iv. Octahedral |
A - i; B - ii; C - iv; D - iii
A - iii; B - ii; C - iv; D - i
A - i; B - iii; C - ii; D - iv
A - ii; B - iv; C - i; D - iii
According to MOT which of the following is correct for potassium hexa cyano ferrate (III)?
It is octahedral complex.
t2g orbital contains the e- of metal.
For iron, overlapping between empty orbitals and ligand orbitals takes place.
All of the above
D.
All of the above
For the complex [Fe(CN)6]4-
Oxidation state of Fe = +II
Co-ordination number = 6
Electronic configuration of Fe2+ =
1s2, 2s2 2p6, 3s2 3p6 3d6, 4s0 4p0
Since, -CN is ligand of strong field, hence it paired up electrons of d-orbital.
So, [Fe(CN)6]4-
Hybridisation = d2sp3
Magnetic moment = zero
Number of upaired electrons = zero
Geometry = octahedral
The shape of water molecule according to VSEPR theory, is
octahedral
distorted tetrahedral
trigonal planar
trigonal bipyramidal