138.
Following reaction takes place in one step:
How will the rate of the above reaction change if the volume of the reaction vessel is diminished to one third of its original volume? Will there be any change in the order of the reaction with the reduced volume ?
The below reaction take place in one step, thus rate of reaction is
Suppose x moles of NO and Y moles of O2 are taken in the vessle of volume V litre, then
If the volume of vessel is reduced to V/3, then for the same moles of NO2 and O2
The rate of the reaction becomes 27 times the initial rate. Order of reaction remains unaffected.
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