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 Multiple Choice QuestionsShort Answer Type

181. State any one condition under which a bimolecular reaction may be kinetically first order.
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 Multiple Choice QuestionsLong Answer Type

182. The time required for 10% completion of a first order reaction at 298 K is equal to that required for its 25% completion at 308 K, if the value of A is 4 x 1010 s–1. Calculate k at 318 k and Ea
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183. The rate constant increases 50% when temperature is increased from 298 K to 308 K. THe value of ΔH0 is 15 kJ mol. Calculate the activation energies Eaf and Ear.
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184. The energy of activation for a reaction is 100 kJ mol–1. The presence of a catalyst lowers the enregy of activation by 75%. What will be the effect on rate of reaction at 20% C, other things being equal.
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 Multiple Choice QuestionsShort Answer Type

185. The difference in energy of activation for uncatalysed reaction and catalysed reaction is 20 kJ/mol. How many times the rate constant of catalysed reaction will increase over the uncatalysed reaction?
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 Multiple Choice QuestionsLong Answer Type

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186.

(a) The decomposition of N2O5(g) is a first order reaction with a rate constant of 5 x 10–4 sec–1 at 45°C.
i.e., 2N2O5(g) = 4NO2(g) + O(g)
If initial concentration of N2O5 is 0.25, calculate its concentration after two minutes. Also calculate half life for the decomposition of N2O5(g).
(b) For an elementary reaction: 2A + B → 3C The rate of appearance of C at time ‘t’ is 1.3 x 10–4 mol l–1 s–1. Calculate at this time:
(i) Rate of reaction (ii) Rate of disappearance of A.


Rate constant K = 5 x 10–4 sec. Initial concentration [A]0 = 0.25 M Final concentration [A]t =? Time taken by the reaction, t = 2 min.
For a first order reaction, rate constant (K) is given by
                        K = 2.303tlog A0At


5×10-4 = 2.303tlog0.25At5×10-4×22.303 = log 0.25 - logAt           0.0004  = log 0.25 - logAt           0.0004 = 0.3979 - log At0.0004 - 0.3979 = -logAt              -0.3975 = -logAt                         At = antilog (0.3975)                          At = 2.6


(b) 2A+B   C

(i) The rate of appearance of C at time t

                              = 1.3 × 10-4 mol L-1 s-1

-ddt[C] = 12ddtA = +12ddtB

(ii) Rate of disappearance of A

                  = 2 × 1.3 × 10-4 mol L-1 S-1=2.6 × 10-4 molL-1 S-1.

                    




































































































































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187. A first order reaction is 50%. Complete in 30 minutes at 27° and in 10 minutes at 47°C. Calculate the reaction rate constant at 27°C and the energy of activation of the reaction in kJ/mol.
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188. In the Arrhenius equation for a certain reaction, the value of A and Ea (activation energy) are 4 x 1023 sec–1 and 98.6 kJ mol–1 respectively. If the reaction is of first order at what temperature will its half life period be ten times.
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 Multiple Choice QuestionsShort Answer Type

189. The rate of a particular reaction triples when temperature changes from 50°C to 100°C. Calculate the activation energy of the reaction. [log 3 = 0.4771 (R = 8.314 ] K–1mol–1)
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190. A certain reaction is 50% complete in 20 minutes at 300 K and the same reaction is again 50% complete in 5 minutes at 350 K. Calculate the activation energy if it is a first order reaction. [R = 8.314 J K–1 mol–1, log 4 = 0.602].
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