S.No. |
A(M) |
B(M) |
Initial rate (M) |
1. |
1.00 |
1.00 |
1.2 x 10–2 |
2. |
1.00 |
2.00 |
4.8 x 10–2 |
3. |
1.00 |
4.00 |
1.9 x 10–1 |
4. |
4.00 |
1.00 |
4.9 x 10–2 |
Assuming that rate law can be written as
Determine the value of
We have given intial concentration 2x10-3and 1x10-3.
the intial concentration equal to 2.40 x 10-4 Ms-1 and 0.60 x10-4 MS-1
Let the rate be =
From the trial (i) and (ii), we get
or
Thus reaction is of second order
The decomposition of H2O2 in basic solution is first order in H2O2.
2H2O2(aq) → 2H2O2 (l) x O2(g)
the rate constant is 1.6 x 10–5 s–1 at 25°C and initial concentration of H2O2 is 0.20 M.
(a) What is the concentration of H2O2 after 2 hrs.
(b) How long will it take for H2O2 concentration to drop to 0.08 M.
(c) How long will it take for 90% of H2O2 to decompose?
t in seconds |
0 |
900 |
1800 |
Cone. of A |
50.8 |
19.7 |
7.62 |
Prove that the reaction is of first order of A to decompose to one-half.
t/sec | 1242 sec | 2745 sec | 4546 sec |
At Conc. | -27.80ml | -29.70ml | -31.81ml |
t (in mitt) |
0 |
135 |
339 |
683 |
1680 |
C (mol L–1) |
2.08 |
1.91 |
1.68 |
1.35 |
0.57 |
Find the order of reaction and calculate its rate constant.
Catalytic decomposition of nitrous oxide by gold at 900°C at an initial pressure of 200 mm was 50% in 53 minutes and 73% in 100 minutes.
(i) What is the order of reaction?
(ii) How much will it decompose in 100 minutes at the same temperature but at an initial pressure of 600 mm?