Let rate k(CCH3COF)a (CH2O)b
CH2O >> CCH3COF and in the second case, CH2O << CCH3COF. In the first case we determine the order of the reaction with respect to CH3 COF. We note that the reaction is not of zero order as rate of reaction changes with time.
Therefore k(CH2O) = 0.0154 min–1 and we note the order of reaction with respect to CH3COF is 1.
Now we determine the order of raction with respect to water.
Again,
The reaction is first order in H2O and we have
For the hydrolysis of methyl acetate in aqueous solution, the following results were obtained:
t/s |
0 |
30 |
60 |
[CH3COOCH3] / mol L–1 |
0.60 |
0.30 |
0.15 |
(i) Show that it follows pseudo-first order reaction, as the concentration of water remains constant.
(ii) Calculate the average rate of reaction between the time intervals 30 to 60 seconds.
(Given log 2 = 0.3010, log 4 = 0.6021)
For a reaction A + B → P, the rate is given by Rate = k[A] [B]2
(i) How is the rate of reaction affected if the concentration of B is doubled?
(ii) What is the overall order of reaction if A is present in large excess?
A first order reaction takes 30 minutes for 50% completion. Calculate the time required for 90% completion of this reaction.
(log 2 = 0.3010)
The following data were obtained during the first-order thermal decomposition of SO2Cl2 at a constant volume:
SO2Cl2(g)---> SO2(g) + Cl2(g)
Experiment |
Time/s-1 |
Total pressure/atm |
1 |
0 |
0.4 |
Calculate the rate constant. (Given : log 4 = 0.6021, log 2 = 0.3010)
A reaction is second order in A and first order in B.
(i) Write the differential rate equation.
(ii) How is the rate affected on increasing the concentration of A three times?
(iii) How is the rate affected when the concentrations of both A and B are doubled?
A first order reaction takes 40 minutes for 30% decomposition. Calculate t1/2 for this reaction.
(Given log 1.428 = 0.1548)
For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction.
Rate constant ‘k’ of a reaction varies with temperature ‘T’ according to the equation:
where Ea is the activation energy.
When a graph is plotted for a straight line with a slope of -4250 K is obtained. Calculate ‘Ea’ for the reaction.
(R = 8.314 JK-1 mol-1)