The reaction 2NO2(g) + O2(g) ⇌ 2NO2(g) is of

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 Multiple Choice QuestionsMultiple Choice Questions

441.

The time required for a first order reaction to complete 90% is 't'. What is the time required to complete 99% of the same reaction?

  • 2t

  • 3t

  • t

  • 4t


442.

The half-life of a radioactive element is 30min, one sixteenth of original quantity of element will remain unchanged after

  • 1 h

  • 16 h

  • 4 h

  • 2 h


443.

If the amount of radioactive substance is increased three times, the number of atoms disintegrated per unit time would

  • be double

  • be triple

  • remain one third

  • not change


444.

Half-life of a radioactive element is 100yr. The time in which it disintegrates to 50% of its mass, will be

  • 50 yr

  • 200 yr

  • 100 yr

  • 25 yr


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445.

20% of a first order reaction was found to be completed at 10 a.m at 11.30 a.m. on the same day, 20% of the reaction was found to be remaining. The half life period in minutes of the reaction is

  • 90

  • 45

  • 60

  • 30


446.

The term (dc/ dt)in a rate equation refers to the

  • concentration of the reactant

  • decreases in concentration of the reactant with time

  • increase in concentration of the reactant with time

  • velocity constant of the reaction


447.

If the rate expression for a chemical reaction is given by rate = k[A]m[B]n

  • the order of the reaction is m

  • the order of the reaction is n

  • the order of the reaction is m + n

  • the order of the reaction is m- n


448.

Unit of first order rate constant is

  • mol L s

  • mol-1 L-1 s-1

  • mol L-1 s-1

  • s-1 or min-1


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449.

For a first order reaction, velocity constant, k =10-3 s-1. Two third life for it would be

  • 1100s

  • 2200s

  • 3300s

  • 4400s


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450.

The reaction 2NO2(g) + O2(g)  2NO2(g) is of first order. If volume of reaction vessel is reduced to 1/3, the rate of reaction would be

  • 1/3 times

  • 2/3 times

  • 3 times

  • 6 times


C.

3 times

As volume of vessel is reduced to 1/3rd, so the concentration will increase by 3 times. For given Ist order reaction; rate law will be :
Rate ofreaction (R,)= k[NO2]         ...(i)
If concentration increases by three times
Rate of reaction (R, ) = k x 3[NO2] ...(ii)
On dividing both equation

Rate of reaction (R1)Rate of reaction(R2) = k[NO2]k × 3[NO2]3 × Rate of reaction (R1) = Rate of reaction (R2)


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