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 Multiple Choice QuestionsMultiple Choice Questions

701.

What is the activation energy for a reaction if its rate doubles when the temperature is raised from 20°C to 35°C ? (R = 8.314 J mol-1 K-1).

  • 342 kJ mol-1

  • 269 kJ mol-1

  • 34.7 kJ mol-1

  • 15.1 kJ mol-1


702.

A reaction having equal energies of activation for forward and reverse reactions has

  • S = 0

  • G = 0

  • H = 0

  • H = G = S = 0


703.

The rate of a certain reaction is given by, rate = k [H+]n. The rate increases 100 times when the pH changes from 3 to 1. The order (n) of the reaction is

  • 2

  • 0

  • 1

  • 1.5


 Multiple Choice QuestionsLong Answer Type

704.

The bacterial growth follows the rate law, dN/dt = kN where k is a constant and 'N' is the number of bacteria cell at any time. If the population of bacteria (number of cell) is doubled in 5 min find the time in which the population will be eight times of the initial one?


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 Multiple Choice QuestionsMultiple Choice Questions

705.

A piece of wood from an archaeological sample has 5.0 counts min-1 per gram of C-14, while a fresh sample of wood has a count of 15.0 min-1g-1. If half-life of C-14 is 5770 yr, the age of the archaeological sample is

  • 8,500 yr

  • 9,200 yr

  • 10,000 yr

  • 11,000 yr


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706.

Two gases X (molecular weight Mx) and Y (molecular weight My; MY > MX) are at the same temperature T in two different containers. Their root mean square velocities are CX and CY respectively. If the average kinetic energies per molecule of two gases X and Y are EX and EY respectively then which of the following realation(s) is (are) true?

  • EX > EY

  • CX > CY

  • EX = EY = (3/2) RT

  • EX = EY = (3/2) kBT


B.

CX > CY

D.

EX = EY = (3/2) kBT

Given, molecular weight of X = MX

Molecular weight of Y = MY and MY > MX

Root mean square velocities = CX and CY respectively

Average KE/ molecule = EX and EY respectively

We know that, 

Root mean square velocity,

C = 3RTM or C ∝ 1M

 CXCY = MYMX

Since, MY > MX

 CX > CY

KE/ molecules = 32nRT

⇒ EX ≠ EY ≠ 32RT

Further, EX = EY33kBT


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707.

A plot of ln K against 1/T (abscissa) is expected to be a straight line with an intercept on ordinate axis equal to:

  • S°2.303R

  • S°R

  • -S°R

  • R xSo


708.

If nt number of radio atoms are present at time t, the following expression will be a constant

  • ntt

  • lnntt

  • ddt(ln nt)

  • t·nt


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709.

The following graph shows how t1/2 (half-life) of a reactant, R changes with the initial reactant concentration a0. The order of the reaction will be

  • 0

  • 1

  • 2

  • 3


710.

The time taken for 10% completion of a first order reaction is 20 min. Then, for 19% completion, the reaction will take

  • 40 min

  • 60 min

  • 30 min

  • 50 min


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