Write the hybridisation and number of unpaired electrons in the complex [CoF6]3-.
Atomic No. of Co = 27
Sc3+ is colourless in aqueous solution whereas Ti3+ is coloured.
Electronic configuration of Ti3+ is [Ar]3d2 4s2. Metal ions usually form hexacoordinated complexes with water molecules. According to Crystal field theory [Ti(H2O)6]+3, Ti3+ ion has outer shell configuration as There is an electron free to jump between energy level. Thus Ti3+ ions selectively absorb certain colours, hence its solution is coloured.
SC3+, on the other hand, has an empty d orbital; the [Sc(H2O)6]+3 complex has no electrons in T2g or eg orbitals. Hence SC3+ is colourless in aqueous solution.
The number of unpaired electrons in[NiCl4]2-, Ni(CO)4 and (Cu(NH3)4]2+ respectively are
0, 2, 1
2, 0, 1
0, 2, 1
2, 2, 0
The pair having the same magnetic moment is:
[At. No. : Cr=24, Mn=25, Fe=26, Co=27]
[Cr(H2O)6 ]2+ and [Fe(H2O)6 ]2+
[Mn(H2O)6 ]2+ and [Cr(H2O)6 ]2+
[CoCl4 ]2− and [Fe(H2O)6 ]2+
[CoCl4 ]2− and [Fe(H2O)6 ]2+