Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

Coordination Compounds

Multiple Choice Questions

471.

The IUPAC name of the complex ion formed when gold dissolves in aqua-regia is

tetrachloridoaurate (III)
tetrachloridoaurate (I)
tetrachloridoaurate (II)
dichloridoaurate (III)

472.

Which of the following will be able to show geometrical isomerism?

MA₃B - Square planar
MA₂B₂ - tetrahedral
MABCD- saquare planar
MABCD- tetrahedral

473.

The complex formed when Al₂O₃ is leached from bauxite using conc. NaOH solution is,

Na[Al(OH)₄]
NaAl₂O₄
Na[Al(OH)₃]
Na₂AlO₂

474.

The number of isomers possible for the octahedral complex [CoCl₂(en)(NH₃)₂]⁺ is

two
three
no isomer
four isomers

475.
The complex ion having minimum magnitude of Δ_° (CFSE) is

[Cr(CN)₆]^3-

[Co(CN₃)₆]³⁺

[Co(Cl)₆]³⁺

[Cr(H₂O)₆]³⁺

[Co(Cl)₆]³⁺

CFSE has lower value, when the complex contains weak field ligand. Thus, CFSE decreases in order.

[Co(NH₃)₆]³⁺ > [Cr(CN)₆]^3- ≈ [Cr(H₂O)₆]³⁺ > [Co(Cl)₆]^3-

Because order of field strength is Cl^- <H₂O <NH₃ <CN^-

^{$CFSE (∆_{°}) is calculated by using the formula CFSE = (- 0.4 x + 0.6 y) ∆_{°} where, x = number of electrons in t_{2 g} and y = number of electrons in e_{g} For {Co}^{3 +} d^{6} high spin in [Co (Cl)_{6}]^{3 -} ∆_{°} = 4 \times (- 0.4) + (2 \times 0.6) = 0.4 ∆_{°} For {Co}^{3 +} d^{3} low spin in [Cr (CN)_{6}]^{3 -} [Cr (H_{2} O)_{6}]^{3 +} ∆_{°} = 3 \times (- 0.4) = - 1.2 ∆_{°} For {Co}^{3 +} d^{6} low spin in [Co ({NH}_{3})]^{3 +} ∆_{°} = 6 \times (- 0.4) + (0 \times 0.6) = - 2.4 ∆_{°} For [Co (Cl)_{6}]^{-} complex magnitude of ∆_{°} CFSE is minimum .$}