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 Multiple Choice QuestionsMultiple Choice Questions

481.

Copper sulphate solution, when added to an excess of ammonium hydroxide, forms a complex compound due to :

  • [Cu(NH3)2]2+

  • [Cu(NH3)4]2+

  • [Cu(NH3)6]2+

  • Cu2+


482.

Mohr salt is made up of which combination of salt?

  • Ammonium sulphate and potash

  • Ammonium sulphate and ferrous sulphate

  • Ammonium sulphate and copper sulphate

  • Ammonium sulphate and magnesium sulphate


483.

The coordination number and the oxidation state of the element 'M' in the complex [M(en)2(C2O4)] NO2 {where (en) is ethan 1, 2-diamine} are respectively

  • 6 and 3

  • 4 and 3

  • 6 and 2

  • 4 and 2


484.

In CsCl type structure the co-ordination of Cs+ and Cl- are:

  • 6, 6

  • 6, 8

  • 8, 8

  • 8, 6


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485.

The IUPAC name of K2[PtCl6] is:

  • hexachloroplatinate potassium

  • potassium hexachloroplatinate (IV)

  • potassium hexachloroplatinate

  • potassium hexachloroplatinum (IV)


486.

Calomel (Hg2Cl2) on reaction with ammonium hydroxide gives

  • HgO

  • Hg2O

  • NH2-Hg-Hg-Cl

  • HgNH2Cl


487.

The isomersim exhibited by following compounds [Co(NH3)6][Cr(CN)6] and [Cr(NH3)6(CN)6] is

  • ionisation isomerism

  • polymerisation isomersion

  • Linkage isomersim

  • Cooridination isomerism


488.

The increasing order of field strenght of ligands is

  • NH3< H2O< Cl-< CO< CN-

  • Cl-< H2O< NH3 < CN-< CO

  • Cl-< CO< CN-< H2O < NH3

  • CN-< CO< NH3< Cl- < H2O


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489.

Which one of the following does not exhibit geometrical isomerism?

  • Octahedral complex with formula [MX2L4]

  • Square planar complex with formula [MX2L2]

  • Tetrahedral complex with formula [MAB XL]

  • Octahedral complex with formula [MX2(L -L)2]


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490.

Which of the following metal ions has a calculated magnetic moment value of ✓24. BM?

  • Mn2+

  • Fe2+

  • Fe3+

  • Co2+


B.

Fe2+

We know that, magnetic moment (μ) is related to number of unpaired electrons 'n' as μeff = √n(n+2) BM

 μeff = √24 BM

This corresponds, n= 4as  μeff = √4(4+2) = √24

                    = 2.√2.√3

                   = 2× 1.414 ×1.732 = 4.89BM

(Trick =Number of unpaired e- are equal to value of variable numberof BM)

Out of given options, Fe2+ has 4 unpaired electrons as

  


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