134.
How much charge is required for the following reductions:
1 mol of Cu2+ to Cu?
Formula required charge n × F
n = difference of charge on ions
F is constant and equal to 96487 Coulombs
Here n = 2
plug the value in formula we get
Required charge= 2 × 96487 Coulombs
= 192974 Coulombs
= 1.93 × 105 Coulombs
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