The specific conductance of a saturated solution of AgCl in water

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 Multiple Choice QuestionsShort Answer Type

271. The conductivity of 0.1 M KCl solution at 298 K is 0.0129 s cm–1. The resistance of this solution in a conductivity cell is found to be 58 ohms. What is the cell constant of the cell? The 0.1 M AgNO3 solution at 298 K in the same conductivity cell offered a resistance of 60.5 ohms. What is the conductivity of 0.1 M AgNO3 solution?
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272. Resistance of a conductivity cell filled with 0.1 M KCl solution is 100 £2. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 Ω. Calculate the conductivity and molar conductivity of 0.02 M KC1 solution. The conductivity of 0.1 M KCl at 298 K is 0.0129 s cm–1.
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273. The electrical resistance of a column of 0.05 M NaOH solution of diameter 1 cm and length 50 cm is 5.55 x 103 ohm. Calculate its resistivity, conductivity and molar conductivity.
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274. 250 cm3 solution containing 1 g of Ca(NO3)2 in conductivity cell offered a resistance of 48 ohms. The cell constant of conductivity of the solution is 0.56 cm-1. Find the molar conductivity.
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275. The conductivity of 0.00241 M acetic acid is 7.896 x 10–5 s cm–1. Calculate its molar conductivity and if Λ°m for acetic acid is 390.5 s cm2 mol–1, what is its dissociation constant?
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276. Λ°m for NaCl, HCl and CH3COONa are 126.4, 425.9 and 91.0 s cm2 mol–1respectively. Calculate Λ° for HAC.
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277. The specific conductance of a saturated solution of AgCl in water is 1.826 x 10–6ohm–1 cm–1 at 25°C. Calculate its solubility in water at 25°C. [Given Λm (Ag+) = 61.92 ohm–1 cm2 mol–1 and Λm (CI ) = 76.34 ohm–1 cm2 mol–1]


Λm (AgCl) = λmm (Ag+) + λm (Cl)
                    =61.92 ohm-1 cm2 mol-1 + 76.34 ohm-1 cm2 mol-1= 138.26 ohm-1 cm2 mol-1

         K = 1.826 × 106 ohm-1 cm2
Solubility (in mol L-1) = K×1000 cm3 L-1Am
                                    = (1.826×10-6 ohm-1)×(1000 cm3 L-1)(138.26 ohm-1 cm2 mol-1) = 1.32 × 10-5 mol L-1.
 
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278. Calculate the molar conductance at infinite dilution of ethanoic acid from the following data:
Λ°m (HCl) = 425.9 s cm2 mol–1
Λ°m (CH3COONa) = 91.0s cm2 mol–1
Λ°m (NaCl) = 126.4 s cm2 mol–1
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 Multiple Choice QuestionsLong Answer Type

279. Draw curves to show how the molar conductance of strong electrolytes varies with dilution.
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 Multiple Choice QuestionsShort Answer Type

280. The molar conductivity of KCl solutions at different concentration at 298 K are given below:

C/mol L–1

Λ/s cm2 mol–1

0.000198

0.000309

0.000521

0.000989

148.61

148.29

147.81

147.09

 
Show that a plot between A and C1/2 is a straight line. Determine the values of Λ° and Λ for KCl.
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