The two half-cell reactions of an electrochemical cell is given as
Ag+ + e- → Ag; = -0.3995 V
Fe2+ → Fe3+ + e- ; = -0.7120 V
The value of cell EMF will be
-0.3125 V
0.3125 V
1.114 V
-1.114 V
At 25°C, the molar conductance of 0.007 M hydrofluoric acid is 150 mho cm2mol-1 and its Λ°m = 500 cm2mol-1. The value of the dissociation constant of the acid at the given concentration at 25°C is
7 × 10-4 M
7 × 10-5 M
9 × 10-3 M
9 × 10-4 M
The standard reduction potential Eo for half-reaction are:
Zn Zn2+ + 2e- ; E° = + 0.76V
Fe Fe2+ + 2e- ; E° = + 0.41 V
The EMF of the cell reaction
Fe2+ + Zn Zn2+ + Fe is :
- 0.35 V
+ 0.35 V
+ 1.17 V
- 1.17 V
B.
+ 0.35 V
Zn Zn2+ + 2e- ; E°oxi = + 0.76
or E°red = - 0.76 V
Fe Fe2+ + 2e- ; E° = + 0.41 V
or E°red = - 0.41 V
E°cell = E°cathode (RP) - E°anode (RP)
= - 0.41 - (0.76)
= + 0.35V
The formal potential of Fe3+ /Fe2+ in a sulphuric acid and phosphoric acid mixture (E° = +0.61 V) is much lower than the standard potential (E° = +0.77 V). This is due to
formation of the species [FeHPO4]+
lowering of potential upon complexation
formation of the species [FesO4]+
high acidity of the medium
A cell is represented by Zn|Zn2+ (aq) || Cu2+ (aq)| Cu. Given, Cu2+ + 2e- → Zn, E° = -0.763 V. Write the cell reactions, emf of the cell and state whether the cell reaction will be spontaneous or not?
Cadmium rods are used for which purpese?
Emit electrons
Absorb neutrons
Emit neutrons
Absorb electrons
What is the effect of dilution on the equivalent conductance of strong electrolyte?
Decrease on dilution
Remains unchanged
Increase on dilution
None of the above
In Down's method for the extraction of sodium, the melting point of the electrolyte is lowered by adding
potassium chloride
calcium chloride
both calcium chloride and potassium fluoride
potassium fluoride only
Calcium is obtained by
electrolysis of molten CaCl2
electrolysis of solution of CaCl2 in water
reduction of CaCl2 with carbon
roasting of lime stone