Important Questions of Equilibrium Chemistry | Zigya

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 Multiple Choice QuestionsLong Answer Type

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111. Bromine water (a dilute solution of bromine in water) is brown and weakly acidic because of the equilibrium denoted by the equation:

Br subscript 2 left parenthesis aq right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis space space rightwards harpoon over leftwards harpoon space space space HBrO left parenthesis aq right parenthesis space plus space straight H subscript 3 straight O to the power of plus left parenthesis straight l right parenthesis space plus space Br to the power of minus left parenthesis aq right parenthesis

In solution, Br–(aq) is brown, Br– is colourless and HBrO (hypobromic acid –a weak acid) is colourless. When sodium hydroxide is added to the solution, the solution becomes colourless but the colour returns when hydrochloric acid is added. Explain the observation.

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112. For the exothermic formation of sulphur trioxide from sulphur dioxide and oxygen in gas phase
          space space space space space 2 SO subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space space space 2 SO subscript 3 left parenthesis straight g right parenthesis
straight K subscript straight p space equals space 40.5 space atm to the power of negative 1 end exponent space at space 900 straight K space and space increment subscript straight r straight H to the power of 0 space equals space minus 198 space kJ

(i) write the expression for the equilibrium constant for the reaction;
(ii) at room temperature (300 K) will Kp be greater than, less than or equal to Kp at 900 K;
(iii) how will the equilibrium be affected if the volume of the vessel containing the three gases is reduced, keeping the temperature constant; what happens;
(iv) what is the effect of adding 1 mole He(g) to a flask containing SO2,O2 and SO3 at equilibrium at constant temperature?

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113.

The dissociation of phosgene is represented as follows:

COCl subscript 2 left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space space space CO left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis

When the mixture of these three gases is compressed at constant temperature, what happens to:
(i) the amount of CO in the mixture.
(ii) the partial pressure of COCl2
(iii) the equilibrium constant for the reaction?

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 Multiple Choice QuestionsShort Answer Type

114.

For the equilibrium 2 NOCl left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space space space 2 NO left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis the value of the equilibrium constant KC is 3.75 space cross times space 10 to the power of negative 6 end exponent space space at space 1069 space straight K.  Calculate Kfor the reaction at this temperature.


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115.

For the equilibrium
2 NOC l left parenthesis straight g right parenthesis space space space space rightwards harpoon over leftwards harpoon space space space space 2 NO left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis
the value of the constant, Kis 3.75 space cross times space 10 to the power of negative 6 end exponent space at space 1069 space straight K. Calculate straight K subscript straight p for the reaction at this temperature.
    

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116.

The value of Kc for the reaction CO left parenthesis straight g right parenthesis space plus space 2 straight H subscript 2 left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space space space CH subscript 3 OH left parenthesis straight g right parenthesis is found to be 186.9 at 750K. Calculate the value of straight K subscript straight p comma if partial pressures are expressed in bars.
        

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 Multiple Choice QuestionsLong Answer Type

117. Find out the value of Kc for each of the following equilibrium from the value of Kp:

left parenthesis straight a right parenthesis space 2 space NOCl left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space space space 2 NO left parenthesis straight g right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis semicolon space space straight K subscript straight p space equals space 1.8 space cross times space 10 to the power of negative 2 end exponent space at space 500 straight K
left parenthesis straight b right parenthesis space CaCO subscript 3 left parenthesis straight s right parenthesis space space space space leftwards harpoon over rightwards harpoon space space CaO left parenthesis straight s right parenthesis space plus space CO subscript 2 left parenthesis straight g right parenthesis comma space straight K subscript straight p space equals space 167 space at space 1073 space straight K
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118. At 700K, the equilibrium constant Kp, for the reaction
   2 SO subscript 3 left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space space space 2 SO subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis is 1.8 space cross times space 10 to the power of negative 3 end exponent space straight k space Pa. What is the chemical value in moles per litre of Kfor this reaction at the same temperature?
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 Multiple Choice QuestionsShort Answer Type

119. At 450K, Kp = 2·0 × 1010/bar for the given reaction at equilibrium:
               2 SO subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space 2 SO subscript 3 left parenthesis straight g right parenthesis

What is Kc at this temperature?

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 Multiple Choice QuestionsLong Answer Type

120.

The equilibrium constant at 278K for Cu left parenthesis straight s right parenthesis space plus space 2 Ag to the power of plus left parenthesis aq right parenthesis space rightwards harpoon over leftwards harpoon space space space Cu to the power of 2 plus end exponent left parenthesis aq right parenthesis space plus space 2 Ag left parenthesis straight s right parenthesis is 2.0 space cross times space 10 to the power of 15. In a solution in which copper has displaced some silver ions from the solution, concentration of Cu2+ ions is 1.8 x 10-2 mol L-1 and the concentration of Ag+ ions is 3·0 ×10–9 mol L–1. Is the system at equilibrium?

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