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24. What is the relation between K_p and K_c?

K_p = K_c (RT)^∆n, where K_p is the equilibrium constant in terms of partial pressure.

K_c is the equilibrium constant in terms of concentration, R is gas constant, T is kelvin temperature and ∆n = No. of moles of the gaseous products – No. of moles of the gaseous reactants.

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25. Under what condition in a reversible reaction is K_p = K_c?

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26. Predict which of the following reaction will have appreciable concentration of reactants and products:

left parenthesis straight a right parenthesis space Cl subscript 2 left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space space 2 Cl left parenthesis straight g right parenthesis comma space space straight K subscript straight C space equals space 5 space cross times space 10 to the power of negative 39 end exponent left parenthesis straight b right parenthesis space Cl subscript 2 left parenthesis straight g right parenthesis space plus space 2 NO left parenthesis straight g right parenthesis space space space leftwards harpoon over rightwards harpoon space 2 NO subscript 2 Cl left parenthesis straight g right parenthesis comma space space straight K subscript straight c space equals space 3.7 space cross times space 10 to the power of negative 8 end exponent left parenthesis straight c right parenthesis space Cl subscript 2 left parenthesis straight g right parenthesis space plus space 2 NO subscript 2 left parenthesis straight g right parenthesis space leftwards harpoon over rightwards harpoon space space 2 NO subscript 2 Cl left parenthesis straight g right parenthesis comma space space straight K subscript straight c space equals space 1.8

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27. PCl₅, PCl₃ and Cl₂ are at equilibrium at 500K and having concentration 1·59M PCl₃, 1·59M Cl₂ and 1·41 M PCl₅. Calculate K_c for the reaction:

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28. A quantity of PCl₅ was heated in a 10 litre vessel at 250°C.

PCl subscript 5 left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space PCl subscript 3 left parenthesis straight g right parenthesis plus space Cl subscript 2 left parenthesis straight g right parenthesis.

At equilibrium the vessel contains 0.1 mole of

PCl subscript 5 comma

0.20 mole of

PCl subscript 3

and 0.20 mole of Cl₂. What is the value of equilibrium constant of the reaction?

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29. At equilibrium, the concentration of N₂ = 3·0 × 10^–3 M, O₂ = 4·2 × 10^–3 M and NO = 2·8 × 10^–3 M in a sealed vessel at 800K. What will be K_c for the reaction:

straight N subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space space space 2 NO left parenthesis straight g right parenthesis

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30. The following concentrations were obtained for the formation of NH₃ from N₂and H₂ at equilibrium at 500K. [N₂] = 1·5 × 10^–2 M, [H₂] = 3·0 × 10^–2M and [NH₃] = 1·2 × 10^–2 M. Calculate the equilibrium constant.

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