What is Kc for the following equilibrium when the equilibrium co

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 Multiple Choice QuestionsShort Answer Type

81.

Calculate the units of the equilibrium constant for the following reactions:
space space straight H subscript 2 left parenthesis straight g right parenthesis space plus space straight I subscript 2 left parenthesis straight g right parenthesis space space space rightwards harpoon over leftwards harpoon space space space 2 HI left parenthesis straight g right parenthesis

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82.

What is the significance of equilibrium constant?

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83. What qualitative information can you obtain from the magnitude of equilibrium constant?
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84.

A mixture of straight H subscript 2 comma space straight N subscript 2 space and space NH subscript 3 with molar concentration 3.0 space cross times space 10 to the power of negative 3 end exponent space mol space straight L to the power of negative 1 end exponent comma space 1.0 space cross times space 10 to the power of negative 3 end exponent space mol space straight L to the power of negative 1 end exponent and 2.0 space cross times space 10 cubed space mol space straight L to the power of negative 1 end exponent respectively was prepared at 500 K. At this temperature the value of straight K subscript straight c for reaction straight N subscript 2 left parenthesis straight g right parenthesis space plus space 3 straight H subscript 2 space rightwards harpoon over leftwards harpoon space space space 2 NH subscript 3 left parenthesis straight g right parenthesis comma space space is space 61. Predict whether at this state the concentration of NH subscript 3 will increases or decrease.

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85. Equilibrium constant Kc for the reaction
                 straight N subscript 2 left parenthesis straight g right parenthesis space plus space 3 straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards harpoon over leftwards harpoon space space space 2 NH subscript 3 left parenthesis straight g right parenthesis space at space 500 space straight K space is space 0.061

At a particular time, the analysis shows that composition of the reaction mixture is 3·0 mol L–1 N2, 2·0 mol L–1 H2 and 0·5 mol L–1 NH3. Is the reaction at equilibrium? If not in which direction does the reaction tend to proceed to reach equilibrium?
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86.

The value of straight K subscript straight c for the reaction 2 straight A rightwards harpoon over leftwards harpoon space straight B plus straight C space is space 2 cross times space 10 to the power of negative 3 end exponent. At a given time the composition of reaction mixture is open vertical bar straight A close vertical bar space equals open vertical bar straight B close vertical bar space equals space open vertical bar straight C close vertical bar space equals space 3 space cross times space 10 to the power of negative 4 end exponent straight M. In which direction the reaction will proceed?

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87.

A mixutre of 1.57 mol of N2,  1.92 mol of H2 and 8.13 mol of NH3 is introduced into a 20L reaction vessel at 500K. At this temperature, the equilibrium constant, Kc, for the reaction
straight N subscript 2 left parenthesis straight g right parenthesis space plus space 3 straight H subscript 2 space rightwards harpoon over leftwards harpoon space space space 2 NH subscript 3 left parenthesis straight g right parenthesis is 1.7 space cross times space 10 squared. Is the reaction mixture at equilibrium? If not, what is the direction of the net reaction?

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88. The reaction,
CO left parenthesis straight g right parenthesis space plus space 3 straight H subscript 2 space rightwards harpoon over leftwards harpoon space space space CH subscript 4 left parenthesis straight g right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight g right parenthesis is at equilibrium at 1300K in a 1 L flask. It also contains 0.30 mol of CO, 0.10 mol of H2 and 0.02 mol of H2O and an unknown amount of CH4 in the flask. Determine the concentration of CH4 in the mixture. The equilibrium constant, Kc, for the reaction at the given temperature is 3.90.
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89.

What is Kc for the following equilibrium when the equilibrium concentration of each substance
is: open square brackets SO subscript 2 close square brackets space equals space 0.60 space straight M comma space space open square brackets straight O subscript 2 close square brackets space equals space 0.82 space straight M space and space open square brackets SO subscript 3 close square brackets space equals space 1.90 space straight M ? 
                     2 SO subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 space space rightwards harpoon over leftwards harpoon space space 2 SO subscript 3 left parenthesis straight g right parenthesis


The reversible reaction is
                      

The equilibrium constant Kc is given by

               

Putting the values in expression (1), we have
   
 

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 Multiple Choice QuestionsLong Answer Type

90. One mole of H2O and one mole of CO are taken in a 10 L vessel and heated to 725K. At equilibrium, 40% of water (by mass) reacts with CO according to the equation

straight H subscript 2 straight O left parenthesis straight g right parenthesis space plus space CO left parenthesis straight g right parenthesis space rightwards harpoon over leftwards harpoon space space straight H subscript 2 left parenthesis straight g right parenthesis space plus space CO subscript 2 left parenthesis straight g right parenthesis

Calculate the equilibrium constant for the reaction.
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