The given reversible reaction is
(Decrease in the pressure of HI = 0.2 - 0.04 = 0.16 atm).
Applying the law of chemical equilibrium
Putting the values in expression (1), we have
The value of Kc for the reaction is at If the equilibrium concentration of in air at is what is the concentration of O3?v
Calculate the value of equilibrium constant for the reaction:
There is 10.0 mol of N2, 14·0 mol of O2 and 0·2 mol of NO2 present at equilibrium in a 3·0L vessel at 298K.What will be the effect of increased temperature on the equilibrium constant?