Explain the terms: buffer solution and buffer capacity. from C

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291.

Calculate the degree of hydrolysis of 0.015 M solution of NH4Cl. Given Kb for NH4OH is 1·8 × 10–5, Kw = 10–14at 25°C.

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292.

Explain the terms: buffer solution and buffer capacity.


Buffer solution: A buffer solution may be defined as a solution which resists change in its pH on the addition of water or small amount of acid or base. The ability of the buffer solution to resist change in its pH on the addition of acid or base is called buffer action.

Types of buffer solutions : Buffer solutions are of two types:
(i) Acidic buffer. An acidic buffer is a mixture (equimolar) of a weak acid and its salt with strong base. For example CH3COOH and CH3COONa ; H2CO3 ; H3PO4 and K3PO4.

(ii) Basic buffer. A basic buffer is a mixture (equimolar) of a weak base and its salt with strong acid. For example NH4OH and NH4Cl ; Ca(OH)and CaSO4.
Buffer capacity or Buffer index: The buffer capacity is defined as the amount (number of moles) of the acid or base which when added to 1 litre of the given buffer solution change its pH by unity i.e. 
           

where d[B] = change in the concentration of base
          d[A] = change in the concentration of acid
  or     dpH = change in pH of the buffer solution
     Buffer capacity is always positive, because
  (i) On adding acid to buffer, its pH is decreased i.e. d[A] is positive but dpH is negative so that
(ii) On adding base to a buffer solution, its pH increases, i.e. d[B] and dpH are both positive and hence 
 

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293.

Show with an example how buffer solution resists the action of acid or base towards change in pH.
Or
Discuss the buffer action of:
(i) acidic buffer
(ii) basic buffer.

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294. How will you explain buffer action of aqueous solution of ammonium acetate?
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295.

Calculate the pH of:
(i) an acidic buffer mixture 
(ii) a basic buffer mixture.
Or
Derive Henderson’s equation for an acidic and basic buffer mixture.
Or
Derive the following equation for the pH of an acidic buffer:
pH space equals space pK subscript straight a space plus space log space fraction numerator open vertical bar Salt close vertical bar over denominator open vertical bar Acid close vertical bar end fraction

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 Multiple Choice QuestionsShort Answer Type

296. Calculate the pH value of a solution obtained by mixing 0·083 moles of acetic acid and 0·091 moles of sodium acetate and making the volume 500 ml. Ka for acetic acid is 1·75 × 10–5.
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 Multiple Choice QuestionsLong Answer Type

297. Calculate the pH of a solution obtained by mixing 6·0g of acetic acid and 12·30g of sodium acetate and making the volume of solution to 500 ml. Ka for acetic acid is 1·8 × 10–5
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298. Determine the pH of a solution obtained by mixing equal volumes of 0·015N NH4OH and 0·15N NH4NO3 solutions. (Kb for NH4OH is 1·8 × 10–5).
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299.

Describe Ostwald’s theory of acid-base indicators.
Or
How does Ostwald’s theory explain the colour change of:
(i) Phenolphthalein
(ii) Methyl orange in acid-base titrations?

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 Multiple Choice QuestionsShort Answer Type

300.

How does the concept of solubility product help in finding out the solubility of sparingly soluble salts?

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