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Equilibrium

Short Answer Type

301.

How does the concept of solubility product help in predicting the ionising and precipitating nature of a salt?

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302. Give the main points of difference between solubility product and ionic product.

170 Views

303.

Give the points of difference betw een solubility and solubility product.

108 Views

304. The solubility of silver chloride is 1·06×10^–5 mole per litre at 298K. Find its solubility product.

107 Views

305.

The solubility of Ag₂CrO₄ at 298K is 6·6 × 10^–5 moles/litre. Find its solubility product.

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306. At 298K, the, solubility of silver chloride in water is 0·00188 gL^–. What is its K_sp?

130 Views

307.

The solubility of CaF₂ in water at 298K is 1·7×10^–3 gram per 100 cm³. Calculate the solubility product of CaF₂ at 298K.

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308. Calculate the solubility of A₂X₃ in pure water, assuming that neither kind of ion reacts with water. The solubility product of A₂X₃, K_sp = 1·1 × 10^–23.

352 Views

309.

Calculate the molar solubility of Ni(OH)₂ in 0·10M NaOH. The ionic product of Ni(OH)₂ is 2·0 × 10^–15.

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310.
At a certain temperature, the solubility product of AgCl is 1 × 10^–10, calculate the solubility of AgCl in g/litre.

Let the solubility of AgCl be S mole litre

Applying the law of solubility product,

Molecular mass of AgCl
= 108 + 35.5 = 143.5

Hence solubility of AgCl
= 143.5 x 1 x 10^-5 g L^-1
= 14.35 x 10^-4 g L^-1