A buffer solution contains 0.1 mole of sodium acetate in 1000 cm3 of 0.1 M acetic acid. To the above buffer solution, 0.1 mole of sodium acetate is further added and dissolved. The pH of the resulting buffer is equal to
pKa - log2
pKa
pKa +2
pKa + log 2
The activation energy of a reaction at a given temperature is found to be 2.303 RT J mol-1. The ratio of rate constant to the Arrhenius factor is
0.01
0.1
0.02
0.001
pH value of which one of the following is not equal to one?
0.1 M CH3COOH
0.1 M HNO3
0.05 M H2SO4
50 cm3 0.4 M HCl + 50 cm3 0.2 M NaOH
A buffersolution contains 0.1 mole of sodium acetate dissolved in 1000 cm3 of 0.1 M acetic acid. To the above buffersolution, 0.1 mole of sodium acetate is further added and dissolved. The pH of the resulting buffer is
pKa
pKa + 2
pKa - log
pKa + log 2
H2S is passed into one nm3 of a solution containing 0.1 mole of Zn2+ and 0.01 mole of Cu2+ till the sulphide ion concentration reaches to 8.1 × 10-19 moles. Which one of the following statements is true?
[Ksp of ZnS and CuS are 3 × 10-22 and 8 × 10-36 respectively.]
Only ZnS precipitates
Both CuS and ZnS precipitate
Only CuS precipitates
No precipitation occurs
0.023 g of sodium metal is reacted with 100 cm3 of water. The pH of the resulting solution is
10
8
9
12
1 dm3 solution containing 10-5 moles each of Cl- ions and CrO ions is treated with 10-4 moles of silver nitrate. Which one of the following observations is made?
[KspAg2CrO4 = 4 × 10-12] and [KspAgCl = 1 × 10-10]
Precipitation does not occur
Silver chromate gets precipitated first
Silver chloride gets precipitated first
Both silver chromate and silver chloride start precipitating simultaneously
pH value of which one of the following is not equal to one?
0.1 M HNO3
0.05 M H2SO4
0.1 M CH3COOH
50 cm3 of 0.4 M HCl + 50 cm3of 0.2 M NaOH
The yield of the products in the reaction A2(g) + 2B(g) C(g) + kJ would be higher at
high temperature and high pressure
high temperature and low pressure
low temperature and high pressure
low temperature and low pressure
The equilibrium constant of a reaction is 0.008 at 298 K. The standard free energy change of the reaction at the same temperature is
-11.96 kJ
-5.43 kJ
-8.46 kJ
+11.96 kJ
D.
+11.96 kJ
Standard free energy change, = -2.303 RT log K
= -2.303 × 8.314 × 298 × log 0.008
= -2.303 × 8.314 × 298 × (3 log 2 - 3 log 10)
= -2.303 × 8.314 × 298 × (0.903 - 3.0)
= -2.303 × 8.314 × 298 × (-2.097)
= +11965.16 J
= +11.96 kJ