The pH of 10-8M NaOH is
8.0
6.0
6.96
7.04
D.
7.04
For 10-8M NaOH,
[OH-] = 10-8 + 10-7 (from water)
= 11 10-8
pOH = - log [OH-]
= - log 11 10-8
= 8 - 1.04 = 6.96
Therefore, pH = 14 - 6.96 = 7.04
The pH of 10-8M NaOH is 7.04
For the reaction, 2NO2 2NO + O2, the value of Kp is equal to K. What will the value of Kp for reaction,
NO + O2 NO2
For a chemical reaction, temperature is raised from 25° C to 35° C. The value of equilibrium constant, Kp is doubled . The heat of reaction (H) for the reaction will be :
13.834 kcal
11.714 kcal
10.726 kcal
4.312 kcal
4.0 g molecular PCl5 were heated in a vessel of 6 L volume. At equilibrium state , 50% of PCl5 is dissociated. The equilibrium constant for the reaction is :
0.66 mol L-1
0.33 mol L-1
0.44 mol L-1
0.88 mol L-1
The pH of blood is :
greater than 10
less than 6
greater than 7 and less than 8
greater than 8 and less than 9
In an exothermic equilibrium ,
A + 3B AB3
all the reactants and products are in gaseous state. The formation of AB3 is favoured at :
low temperature and low pressure
low temperature and high pressure
high temperature and high pressure
high temperature and low pressure
A precipitate of AgCl is formed when equal volumes of the following are mixed :
[Ksp for AgCl = 10-10]
10-4 M AgNO3 and 10-7 M HCl
10-5 M AgNO3 and 10-6 M HCl
10-5 M AgNO3 and 10-4 M HCl
10-6 M AgNO3 and 10-6 M HCl