76.
Which will be the main product when the following haloalkanes are treated with alcoholic KOH?
(i) 2-bromobutane
(ii) CH3CH2C(CH3)2Cl.
(i) When 2-bromobutane is treated with alcoholic KOH, it form 2-butene as main product.
(ii) When CH3CH2C(CH3)2Cl is treated with alcoholic KOH, it form CH3CH = C(CH3)2 as main product.
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