Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

Hydrocarbons

Short Answer Type

131.

Alkanes and alkynes do not exhibit geometrical isomerism. Explain.

390 Views

Long Answer Type

132.

How will you explain that there exists two varieties of 1, 2,-dichloroethene while there is only one type of 1, 2-dichloroethane?

102 Views

Short Answer Type

133. Which of the following compounds would show geometrical isomerism? Draw the isomeric structures to support your answer:
(i) But-2-ene
(ii) Pent-1-ene
(iii) 2-Methyl-But -2-ene
(iv) 3, 4-Dimethyl-hex-3-ene

410 Views

134.

Draw cis and trans isomers of the following compounds. Also, write their IUPAC names:

(i) CHCl = CHCl

(ii) C₂H₅CCH₃ = CCH₃C₂H₅

1001 Views

135.

Which of the following compounds will show cis-trans isomerism?

(i)(CH₃)₂C = CH-C₂H₅
(ii) CH₂ = CBr₂(iii) C₂H₅CH = CH-CH₂
(iv) CH₃CH = CClCH₃

469 Views

136.

Draw the cis and trans structures of hex-2-ene. Which isomer will have higher b.p. and why?

361 Views

137.
Out of the two - trans-but-2-ene and cis-but-1-ene, which is more stable and why

Trans-but-2-ene has less heat of hydrogenation than the cis-isomer, therefore it is more stable.

In the trans isomer, the two methyl groups are present on the opposite side as compared to cis-isomer. As a result, the Vander Waal's forces of attraction in trans isomer are less. This means that the trans isomer has less heat of hydrogenation and is more stable than the cis-isomer.