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Hydrocarbons

Short Answer Type

131.

Alkanes and alkynes do not exhibit geometrical isomerism. Explain.

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Long Answer Type

132.

How will you explain that there exists two varieties of 1, 2,-dichloroethene while there is only one type of 1, 2-dichloroethane?

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Short Answer Type

133. Which of the following compounds would show geometrical isomerism? Draw the isomeric structures to support your answer:
(i) But-2-ene
(ii) Pent-1-ene
(iii) 2-Methyl-But -2-ene
(iv) 3, 4-Dimethyl-hex-3-ene

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134.

Draw cis and trans isomers of the following compounds. Also, write their IUPAC names:

(i) CHCl = CHCl

(ii) C₂H₅CCH₃ = CCH₃C₂H₅

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135.

Which of the following compounds will show cis-trans isomerism?

(i)(CH₃)₂C = CH-C₂H₅
(ii) CH₂ = CBr₂(iii) C₂H₅CH = CH-CH₂
(iv) CH₃CH = CClCH₃

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136.

Draw the cis and trans structures of hex-2-ene. Which isomer will have higher b.p. and why?

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137.

Out of the two - trans-but-2-ene and cis-but-1-ene, which is more stable and why

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138.
What happens when 2-Bromobutane is heated with alcoholic KOH. Account for the product formed.

When 2-Bromobutane is heated with alcoholic KOH, but-2-ene is the main product.

Formation of but-2-ene as the major product can be explained by Saytzeff's rule which states that if an alkyl halide undergoes elimination in two different ways, then the more highly substituted alkene i.e. having lesser number of hydrogen atoms on the doubly bonded carbon atoms, is the major product of dehydrohalogenation reaction.

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