Assertion (A): Reaction of 1-butene with HBr gives 1-bromobutane

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

481.

In the following reaction, number of possible structure is

  • 1

  • 2

  • 5

  • 6


482.

In Zeigler Natta polymerisation of ethylene, the active species is

  • AlCl3

  • Et3Al

  • CH2CH2

  • Ti3+


483.

The number of possible alkynes with molecular formula C5H8 is

  • 1

  • 3

  • 5

  • 8


484.

How many delocalised π-electrons are there in the following compound?

  

  • 1

  • 2

  • 3

  • 6


Advertisement
485.

Which of the following is an anti-knocking compound?

  • TEL

  • LTC

  • Freon

  • Gasoline


486.

The cumulated alkadiene is


487.

The IUPAC name of 

   is

  • 4-bromo-2-chloro-5-iodo-1-fluorobenzene

  • 2-carbamoylhex-3-enal

  • 1-bromo-2-chloro-3-fluoro-6-iodobenzene

  • 2-bromo-1-chloro-5-fluoro-3-iodobenzene


488.

Compound  which of the following prefix?

  • trans

  • Anti

  • E

  • Z


Advertisement
489.

Friedel-Crafts reaction is not related with

  • acylation

  • reduction

  • sulphonation

  • nitration


Advertisement

490.

Assertion (A): Reaction of 1-butene with HBr gives 1-bromobutane as major product.

Reason (R): Addition of hydrogen halides to alkenes proceeds according to Markownikoffs rule.

The correct answer is

  • A and R are correct and R is the correct explanation of A

  • A and R are correct but R is not the correct explanation of A.

  • A is correct but R is not correct

  • A is not correct but R is correct


D.

A is not correct but R is correct

According to Markownikoff's rule, the addition of reagents such as HX, H2O and HOX with unsymmetrical alkanes occurs in such a way that the negative part of the adding molecule goes to that carbon atom of the double bond which carries lesser number of hydrogen atoms.

 CH3CH2CH=CH2 + HBrAbsence of peroxidesDark CH3CH2-CHBr-CH32-bromobutane (major product) + CH3CH3-CH2-CH2-Br1- bromobutane ( minor product)


Advertisement
Advertisement