Optically active CH3—CH2—CHOH—CH3 was foun

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

491.

The product (Z) of the following reaction is:

       


492.

What is the product in the following reaction?

  • Benzoquionone

  • Cyclohexane-1-one

  • Benzoic sulphate

  • Benzoric acid


493.

Which one of the following has highest boiling point?

  • H3CCH2CH2CH2Cl

  • (H3C)2CHCH2Cl

  • (H3C)3CCl

  • H3CCH2CHClCH3


494.

The product Z of the following reaction is H3CC≡CH 2HBr Z.

  • H3CCH2CHBr2

  • H3CCBr2CH3

  • H3CCHBrCH2Br

  • BrCH2CH2CH2Br


Advertisement
495.

Identify X and Y in the following reaction sequence

X Zn Y Zn-H2OO3 (CH3)2CO + CH2O

  •  

    X Y
    (CH3)2CHBrCH3 CH3CH=CHCH3
  • X Y
    (CH3)2CHCH2Br CH3CH=CHCH3
  • X Y
    (CH3)2CBrCH2Br (CH3)2C=CH2
  • X Y
    (CH3)2CHCHBr2 (CH3)2C=CH2

496.

Oxidation of cyclohexene in presence of acidic potassium permaganate leads to

  • glutaric acid

  • adipic acid

  • pimelic acid

  • succinic acid


497.

Cyclopentadienyl anion is

  • benzenoid and aromatic

  • non-benzenoid and aromatic

  • non-benzenoid and non-aromatic

  • non-benzenoid and anti- aromatic


498.

The reactivity of alkyl bromides.

 

Towards iodide ion in dry acetone decrease in the order

  • V > I > II > III

  • I > IV> II> III

  • III> II> I> I

  • III > II > IV > I


Advertisement
Advertisement

499.

Optically active CH3—CH2—CHOH—CH3 was found to have lost its optical activity after standing in water containing a few drops of acids, mainly due to the formation of 

  • CH3—CH2—CH=CH2

  • CH3—CH=CH—CH3

  • CH3—CH(CH3)—CH2—OH

  • CH3—CH2—CH2—CH2—OH


B.

CH3—CH=CH—CH3

CH3—CH2—CHOH—CH3 (Dehydration)Few drops of acid CH3—CH=CH—CH3.

The above optically active compound undergo dehydration with few drops of acid and form stable alkene through the formation of stable carbocation.


Advertisement
500.

Which one of the following alkenes when treated with HCl yields majority an anti Maxkovnikov product?

  • CH3O-CH=CH2

  • Cl-CH=CH2

  • F3C-CH=CH2

  • H2N-CH=CH2


Advertisement