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(i) With chlorine. H 2 reduces chlorine into chloride (Cl - ) ion and itself get oxidised to H + ion by chlorine to form HCl. An electron pair is shared between H and Cl leading to the formation of a covalent molecule. H 2 +Cl 2 --> 2HCl (ii) With sodium. H 2 is reduced by sodium to form NaH. An electron is transferred from Na to H leading to the formation of Na + H - (ionic compound). (iii) With copper (II) oxide. H 2 reduces copper (II) oxide to copper and itself gets oxidised to H 2 O, which is a covalent molecule. CuO +H 2 ---> Cu +H 2 O

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Hydrogen

Short Answer Type

81.

Complete the following reactions:

$bold CO bold left parenthesis bold g bold right parenthesis bold space bold plus bold space bold H subscript bold 2 bold left parenthesis bold g bold right parenthesis bold space bold space bold rightwards arrow from bold Catalyst to bold increment of$

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82.

Complete the following reactions:

$CuO left parenthesis straight s right parenthesis space plus space straight H subscript 2 left parenthesis straight g right parenthesis space space rightwards arrow$

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83. Comment on the reactions of dihydrogen with: (i) chlorine (ii) sodium and (iii) copper (II) oxide.

(i) With chlorine. H₂ reduces chlorine into chloride (Cl^-) ion and itself get oxidised to H⁺ ion by chlorine to form HCl. An electron pair is shared between H and Cl leading to the formation of a covalent molecule.

H₂ +Cl₂ --> 2HCl

(ii) With sodium. H₂ is reduced by sodium to form NaH. An electron is transferred from Na to H leading to the formation of Na⁺H^- (ionic compound).

(iii) With copper (II) oxide. H₂ reduces copper (II) oxide to copper and itself gets oxidised to H₂O, which is a covalent molecule.

CuO +H₂ ---> Cu +H₂O