Short Answer TypeWhat are the oxidation number of the underlined elements in each of the following and how do you rationalise your results?
What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results?
What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results?
What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results?
What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results?
Â
Long Answer TypeCalculate the oxidation number of sulphur, chromium and nitrogen in H2SO5, 
 and 
 Suggest structure of these compounds. Count for the fallacy.
Short Answer TypeLong Answer TypeCalculate the oxidation number of:
(i) Cr in dichromate ion
(ii)Â Mn in manganate ion
(iii)Â S in tetrathionate ion.
(i) Let the oxidation number of Cr in dichromate ion 
Writing the oxidation number of each atom at the top of its symbol
              
The algebraic sum of oxidation number of various atoms = 2
          2(x) + 7(-2) = 0
or           2x - 14 = -2
               2x =  12
             x = +6
(ii) Let the oxidation number of Mn in manganate ion 
     Writing the oxidation number of each atom at the top of its symbol
                x       -2
               [Mn      O4]2-
The algebraic sum of the oxidation number of various atoms = -2
         x + 4(-2) = -2
           x - 8 = -2
           x = +6
(iii) Let the oxidation number of S in tetrathionate ion 
      Writing the oxidation number of each atom at the top of its symbol.
               x        -2
              [S4       O6]2-
     The algebraic sum of oxidation number of various atoms = -2
            4(x) + 6(-2) = -2
          or   4x - 12 = -2
          or       4x = 10
Therefore , Â x = 5/2.
Short Answer Type
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