Compute the oxidation number of Co in [CO(NH3)5Br] from Chemi

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 Multiple Choice QuestionsShort Answer Type

111.

What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results?
straight K bottom enclose straight I subscript 3

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112.

What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results?
straight H subscript 2 bottom enclose straight S subscript 4 end enclose straight O subscript 6

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113.

What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results?
bottom enclose Fe subscript 3 end enclose straight O subscript 4



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114.

What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results?

bold space bold space bottom enclose bold C bold H subscript bold 3 bottom enclose bold C bold H subscript bold 2 bold OH




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115.

What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results?
bottom enclose straight C straight H subscript 3 bottom enclose straight C OOH 





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 Multiple Choice QuestionsLong Answer Type

116.

Calculate the oxidation number of sulphur, chromium and nitrogen in H2SO5space space Cr subscript 2 straight O subscript 7 superscript 2 minus end superscript and space space NO subscript 3 superscript minus Suggest structure of these compounds. Count for the fallacy.

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 Multiple Choice QuestionsShort Answer Type

117. Calculate the oxidation number of Fe in K4|Fe(CN)6|.
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 Multiple Choice QuestionsLong Answer Type

118.

Calculate the oxidation number of:
(i) Cr in dichromate ion
(ii) Mn in manganate ion
(iii) S in tetrathionate ion.

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119.

Compute the oxidation number of:
(i) Ni in |Ni(Fe(C2O4)3|
(ii) Fe in K3|Fe(C2O4)3|

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 Multiple Choice QuestionsShort Answer Type

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120.

Compute the oxidation number of Co in [CO(NH3)5Br]SO subscript 4 superscript negative 2 end superscript


Let the oxidation number of Co =x
Writing the oxidation number of each atom at the top of its symbol,
  x     0     -1
[CO(NH3)5Br]
The algebraic sum of the oxidation number of various atoms = 0
       x + 5 (0) - 1  =+2(anions charge)
       x-1=2
       x=3
            

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