Balance the following equation by oxidation number method:
(i) The Skeleton equation along with oxidation number of each atom is
+4 -2 0 0 +2 -2
Sn O2 + C Sn+ C O
(ii) Noting the change in O.N. of above atoms,
Increase C = 0 to +2 i.e. 2
Decrease Sn = +4 to 0 i.e. 4
(iii) Equalise the increase/decrease in O.N. by multiplying SnO2 by 1 and C by 2
SnO2 + 2C Sn + CO
(iv) On counting and balancing the atoms on both sides, we get the balanced equation:
SnO2 + 2C Sn + 2CO
Balance the following chemical equation by oxidation number method:
in acidic medium.