(i) The skeleton equation along with O.N. of equation is
+3 -2 0 0 + 2 -2
Fe2O3 + C Fe + C O
Fe = +3 (C = 0) (Fe = 0) (C = +2)
Total O.N. Fe = 6
(ii) Noting the change in O.N. of above atoms,
Increase C = 0 to 2 i.e. 2
Decrease Fe = 3 to 0 i.e. 3
(iii) Equalise the increase/decrease in O.N. by multiplying C by 3
Fe2O3 + 3C Fe + CO
(iv) On counting and balancing the atoms on both sides, we get the balanced equation.
Fe2O3 + 3C 2Fe + 3CO
Balance the following chemical equation by oxidation number method:
in acidic medium.