The Mn3+ ions is unstable in solution and undergoes disproport

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 Multiple Choice QuestionsLong Answer Type

141. Write correctly balanced half reaction and the overall equations for the skeleton equation:
          MnO subscript 4 superscript minus space plus space straight H subscript 2 straight C subscript 2 straight O subscript 4 space space rightwards arrow space space space stack Mn to the power of 2 plus end exponent space plus space CO subscript 2 with left parenthesis in space acid space solution right parenthesis below

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142. Balance the equation by half reaction method (ion-electron method):
straight I subscript 2 space plus space HNO subscript 3 space space rightwards arrow space space space HIO subscript 3 space plus space NO subscript 2 space plus space straight H subscript 2 straight O
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143.

Chlorine is used to purify drinking water. Excess of chlorine is harmful. The excess of chlorine is removed by treating with sulphur dioxide. Present a balanced equation for this redox change taking place in water. 

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144.

The Mn3+ ions is unstable in solution and undergoes disproportionation to give Mn2+MnO2 and H+ ion. Write a balanced ionic equation for the reaction.


The skeleton equation is
Mn3+ (aq) → Mn2+ (aq) + MnO2(s) + H+(aq)
Let us balance the above equation by ion electron method.

1. Write the oxidation and reduction half-reactions by observing the changes in oxidation number and writing these separately
Oxidation half-reaction:
            +3                    +4
            
  Reduction half reaction:
             +3                         +2
             

2. Balancing the oxidation half reaction
(i) Add 1 electron towards R.H.S. to balance the charge on Mn.
                  
(ii) Balance the charges by adding four H+ towards R.H.S.
               
                               [Balanced oxidation half reaction]
(iii) Balance O atoms by adding two H2O molecules downwards L.H.S.
          
                              [Balanced oxidation half reaction]
3. Balancing the reduction half reaction:
         Add 1 electron towards L.H.S. to balance the charge on Mn. 
                   
                                   (Balanced reduction half reaction]
4. Adding balanced oxidation half reaction and balanced reduction half-reaction. 
                     
This is balanced redox equation for disproportionation reaction. 

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 Multiple Choice QuestionsShort Answer Type

145.

Balance the following redox reactions by ion-electron method:
MnO subscript 4 superscript minus left parenthesis aq right parenthesis space plus space SO subscript 2 left parenthesis straight g right parenthesis space rightwards arrow space space Mn to the power of 2 plus end exponent left parenthesis aq right parenthesis space plus space HSO subscript 4 superscript minus left parenthesis aq right parenthesis space left parenthesis in space acidic space solution right parenthesis

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 Multiple Choice QuestionsLong Answer Type

146. Balance the following redox reaction by ion-electron method:
stack MnO subscript 4 superscript minus left parenthesis aq right parenthesis space plus space straight I to the power of minus left parenthesis aq with left parenthesis in space basic space medium right parenthesis below right parenthesis space space space rightwards arrow space space space MnO subscript 2 left parenthesis straight s right parenthesis space plus space straight I subscript 2 left parenthesis straight s right parenthesis
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147.

Permanganate (VII) ion, MnO subscript 4 superscript minus in basic solution oxidises iodide ion, I- to produce molecule iodine (I2) and manganese (IV) oxide (MnO2). Write a balanced ionic equation to represent redox reaction. 

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148.

Balance the following equations in basic medium by ion-electron method and oxidation number method:

straight P subscript 4 left parenthesis straight s right parenthesis space plus space OH to the power of minus left parenthesis aq right parenthesis space rightwards arrow space space PH subscript 3 left parenthesis straight g right parenthesis space plus space HPO subscript 2 superscript minus left parenthesis aq right parenthesis

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149. Balance the following equation in basic medium by ion-electron method and oxidation number method and identify the oxidising agent and the reducing agent.
straight N subscript 2 straight H subscript 4 left parenthesis straight l right parenthesis space plus space ClO subscript 3 superscript minus left parenthesis aq right parenthesis space space rightwards arrow space space space NO left parenthesis straight g right parenthesis space plus space Cl to the power of minus left parenthesis straight g right parenthesis
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150. Balance the following equation in basic medium by ion-electron method and oxidation number method and identify the oxidising agent and the reducing agent.
Cl subscript 2 straight O subscript 7 left parenthesis straight g right parenthesis space plus space straight H subscript 2 straight O subscript 2 left parenthesis aq right parenthesis space space rightwards arrow space space space ClO subscript 2 superscript minus left parenthesis aq right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis space plus space straight H to the power of plus

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