144.
Calculate the amount of benzoic acid (C6H5COOH) required for preparing 250 mL of 0.15 M solution in methanol.
Answer:
Mol. mass of benzoic acid, C6H5COOH
= 6 x 12 + 5 x 1 + 12 + 16 + 16 + 1
= 72 + 5 + 12 + 16+16 + 1
= 122 g mol–1
by using formula;
here x= amount of substance required
Amount of benzoic acid required
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