An aqueous solution of 2 percent non-volatile solute exerts a pressure of 0.096 atm at the boiling poine of the solvent. What is the molecular mass of the solute ?
Answer;
Let the density of solution = d g/cm3
and volume of solution is = 1L = 1000 cm3
mass of the solution = d xV
= (1000d)g
6.90 M solution mean 1L solution contains 6.90 moles of KOH
therefore mass of KOH = 6.90 x 56 = 386.4g
but only 30% of the solutionby mass is KOH
therefore
30/100 x (1000)d =386.4
and density is 1.288g/ cm3