Calculate the vapour- pressure lowering of water when5.67g of glucose, C6H12O6 is dissolved in 25.2 g water at 250C. The vapour pressure of water at 250C is 23.8 mmHg. What is the vapour pressure of the solution?
Answer:
13 % of solution of sulphuric acid contains 13 g of H2SO4in 100 g of the solution. Weight of water = 100 - 13 = 87 g.
mole of H2SO4 = 13/98 mole
Volume of H2SO4 solution + Weight of soluton / Density = 100/1.02 ml
= 100 / 1.02 x 1/1000 = 1/1.02 litre
Molarity of H2SO4 solution = mole of H2SO4 / Volume of solution
= 13/98 / 1/1.02 = 10.2 x 13/98 = 1.353 M
Molality of H2SO4 solution = mole of H2SO4 / wt of water in kg. = 13/98 / 87/1000 = 13/98 x 1000/87
= 1.525 mol kg-1 (mole Kg-1)
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