Give reasons for the following:Elevation of the boiling point of

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsShort Answer Type

271.

A 10% solution (by mass) of sucrose in water has the freezing point of 269.15 K.Calculate the freezing point of 10% glucose in water if freezing point of pure water is273.15 K.

Given : (Molar mass of sucrose = 342 g mol–1) (Molar mass of glucose = 180 g mol–1)

3173 Views

272.

Write one difference in each of the following:
Solution and Colloid

1065 Views

273.

Calculate the freezing point of a solution containing 60 g of glucose (Molar mass = 180 g mol–1) in 250 g of water.
(Kf of water = 1.86 K kg mol–1)


274.

Give reasons for the following :

Measurement of osmotic pressure method is preferred for the determination of molar masses of macromolecules such as proteins and polymers.


Advertisement
275.

Give reasons for the following:

Aquatic animals are more comfortable in the cold water than in warm water.


Advertisement

276.

Give reasons for the following:

Elevation of the boiling point of 1 M KCl solution is nearly double than that of 1 M sugar solution.


The elevation of boiling point is Δtb = iKbm in both 1M KCl & 1 M sugar. As colligative property depends only on a number of particle and KCl as electrolyte will produce a double number of a particle of sugar. Hence the value van’t hoff factor is twice in 1m KCl then 1M sugar due to which elevation in boiling point is more.


Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

277.

18 g glucose (C6H12O6 ) is added to 178.2 g water. The vapor pressure of water (in torr) for this aqueous solution is:

  • 76.0

  • 752.4

  • 759.0

  • 759.0

422 Views

278.

The vapour pressure of acetone at 20oC is 185 torr. When 1.2 g of a non-volatile substance was dissolved in 100 g of acetone at 20oC, its vapour pressure was 183 torr. The molar mass (g mol-1 ) of the substance is:

  • 32

  • 64

  • 128

  • 128

514 Views

Advertisement
279.

3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is:

  • 18 mg

  • 36 mg

  • 42 mg

  • 42 mg

424 Views

280.

For the estimation of nitrogen 1.4g of an organic compound was digested by Kjeldahl's method and the evolved ammonia was absorbed in 60 mL of M/10 sulphuric acid. The unreacted acid required 20 mL of M/10 sodium hydroxide for complete neutralisation. The percentage of nitrogen in the compound is 

  • 6%

  • 10%

  • 3%

  • 3%

386 Views

Advertisement